Compute √a like a #Babylonian….
From FB
1) Make a guess x₀ > 0 for √a
2) The average x₁ = ½ (x₀ +a/x₀) is closer to √a than either x₀ or a/x₀
3) Iterating step 2 gives you a sequence x₁, x₂, x₃, … that converges to √a .
Babylonian square root
Paolo Redaelli personal blog
A civil engineer with a longlife fondness for Software Libero